Recent content by nevetsnosaj

thanks... physics is sure a lot of fun.

thanks... then the m3 should be 50.71 from (75)(125)+(20)(-25)+(m3)(175)=0

so we're supposed to to this? m1x1+m2x2+m3x3=0 (75)(125)+(20)(-50)+(m3)(-175)=0 175m3=8375 m3 = 47.86 kg

OK so it's going to be: m1x1 + m2x2 = 0 (75)(125)+(m2)(-175) =0 175m2=9375 m2=53.57 kg (x2 is negative because m2 is on the other side of m1 and the COM is the zero point) I've never done it. I'm learning how to do it. Now I understand about the moments eqn. Thanks for the help.

opps... that's a typo... So i get it right, don't i? I don't know what is the moment eqn . Can you tell me the equation?

Ricardo to COM = 175 cm Carmelita to COM = 125 cm and what's the formula of the moment eqn ?

ok. I get it. So since the COM change, the canoe moves. I've figured out the distance between each person to the COM after the switching. What am I supposed to do with that number?

i got confused with the COM and wrt. Isn't COM is Conservation of Momentum?

so with that we can use the conservation of momentum and eliminate the Velocity and then find the mass of Carmelita?

x1 = ricardo = 3m x2 = canoe = 50 cm x3 = carmelita = 3m that's what i did.

i'm using his formula and just plug the number in. I think when Ricardo moving, he made the canoe moved for a certain distance. (the lake and the canoe is frictionless so that the momentum that ricardo give to the canoe makes the canoe move) When carmelita move, she make the canoe move to the...

i did m1x1 - m3x3 = m2x2 and i got 71.67 as the mass of Carmelita. Is that the right answer? m1 = Ricardo m2 = Canoe m3 = Carmelita

I saw that you round up the decimal. I did it without rounding anything.

is the answer 1834.802 ?

the equation that you're supposed to use is W = F d Didn't you get the distance in the problem? Why did you try to find it with trig.? If you have to find d with cosine, then what's 4.6 m for?