I kind of understand your method of adding 90 and 180, etc. I've never been taught to use your method with the quadrants, etc. About the angle I determined, I think it is in the first quadrant based on my free body diagram. Your drew yours in the opposite direction that I drew mine. So, I didn't...
I'm afraid I don't understand how you worked your problem either. Your using the same equations that I just said I didn't understand. Also, I didn't get why you were adding 90 and 180 to theta. I'd really appreciate it if my questions about the equations I listed were answered because I feel I...
Well, here, perhaps this help clarify why I'm lost. Here are the equations that were used by the website I found the problem on.
X component: 0=theta R=radial/radius
mgsin0 + F(friction)cos0=maR
FNsin0 + muFNcos0=m(v2/r)
How are these two equations related? They both...
I've seen the diagram that takes into account static friction. Since I've seen the problem worked out before. But it was on another website, and I wasn't able to ask questions on there. The second diagram didn't help me though, because it didn't help to clarify why friction had a vertical...
If a curve with a radius of 88m is perfectly banked for a car traveling 75km/h, what must be the coefficient of static friction for a car not to skid when traveling at 95km/h?
Relevent equations: F=ma, Fr=muFN
FNsintheta=m(v2/radius) = mg/costheta x sintheta = m(v2/r) = mgtantheta =...