urgent. Growth in salmon smolt
Homework Statement
smolt weith is 35g we shall find the weight after 61 days.
Homework Equations
specific growth rate:; K' = Ln (N2 / N1) / (t2 - t1)
growth rate is 1,9 %
The Attempt at a Solution
I find 110g when I use this forumula...
Ok :) thanks for the advice.
But what do I now
Is it just to add the heat from the container 55000J too the 4 parts added = 3804000J
= 3804000J + 55000J = 3859000J ?
hmm Starting temprature of the container must be -10 Celsius and ending temprature of 100Celsius ?
So then the heat from container is 500j/k *110K = 55000J ?
Ok I think what I dont seems to find now is the
Also set your equations equal to one another. Energy lost = energy gained ect...I had the same problem awhile back and thats what I was leaving out.
hmm is the energy lost in the phase changes ?
What I tryed is:
Water Q=mt = 0,3*4190 = 1257J
Ice to liquid: Q=mt = 0,15*334000 = 50100J
1) The melted Ice is now water of 0C = (0,15kg)*(4190)j/kg*K)(T-0)
2) The water of 50c = (0,3kg)*(4190)j/kg*K)(T-50)
solving that (0,15)*(4190)= 628,6T...
Aii yes it is 500J/K not Kg :)
I tryed to find the heat gained from ice to vapor.
1: Ice heats up to melting point
Q=mcdeltaT = 2kg*2100j/kg*K*10K = 42000J
2: Ice melts at C0
Q=+-ml = 2kg* 334000J = 668000J
3: liquid water of C0 heats up to 100C
Q=mcdeltaT = 2kg*4190j/kg*K*100K...