Recent content by Newtons Balls

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    Change of basis- contravariant, covariant components of a vector.

    Homework Statement Let e_{i} with i=1,2 be an orthonormal basis in two-dimensional Euclidean space ie. the metric is g_{ij} = \delta _{ij}. In the this basis the vector v has contravariant components v^{i} = (1,2). Consider the new basis e_{1}^{'} = 5e_{1} - 2e_{2} e_{2}^{'} = 3e_{1} - e_{2}...
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    What is the 4-momentum of a particle with given rest mass and speed?

    lol. Thanks so much for your help :D I owe you a pint of e-beer :)
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    What is the 4-momentum of a particle with given rest mass and speed?

    E=m \gamma c^{2} P=mv\gamma So: v=c^{2}P/E Right?
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    What is the 4-momentum of a particle with given rest mass and speed?

    I found that equation on the interwebs because part a of the question is to state the relativistic relationship between Mass, Energy and Momentum and I can't find anything with all three in this textbook. The best I can find in the book is this: c^{2}m^{2} - p^{2} = c^{2}m0^{2} I reckon m0 is...
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    What is the 4-momentum of a particle with given rest mass and speed?

    *groan* I've just been trying to sort out the units. Doesn't the initial relativistic equation mean P and E must be dimensionally the same? m^{2} = E^{2} - p^{2} Then how can the velocity be E/p, as that would make it dimensionless?
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    What is the 4-momentum of a particle with given rest mass and speed?

    Its definitely c(2\sqrt2,1,0,-1) And as for the textbook, it is the recommended text for the module. I haven't sat the module which explains my nubbishness. Long story short I have to teach myself this module over the summer for next year :( The textbook isn't very good for self learning...
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    What is the 4-momentum of a particle with given rest mass and speed?

    Anyway, just did the calculation quickly and I get 0.5c, which sounds reasonable. And I got T=\sqrt8-\sqrt6c.. whatever that is. Sound right?
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    What is the 4-momentum of a particle with given rest mass and speed?

    Hmm. No I think you're right about not needing the c^{2}. I keep referring to this textbook and it doesn't use natural units. :(
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    What is the 4-momentum of a particle with given rest mass and speed?

    E=c^{2}m\gamma? Or you mean T? T=E - c^{2}m? I assume you mean use the E equation to work out v, then minus that from E to work out T?
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    Lagrangian Mechanics - Pulley System

    lol. I'm an idiot. I finally see where its from. This will teach me to skip steps and do too much in my head. The displacement of the third mass if R\theta + y The derivative of this wrt time is R\theta ' + y' This squared is R^{2}\theta^{2}' + y'^{2} + 2R\theta'y' I really feel like an idiot :)
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    What is the 4-momentum of a particle with given rest mass and speed?

    Well for v: p=mv\gamma? Unfortunately that doesn't rearrange reasonably... is that equation wrong or am I being an idiot with my re-arranging? ^_^
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    What is the 4-momentum of a particle with given rest mass and speed?

    Thanks. So E=2\sqrt{2}c, p=\sqrt{2}c, m=\sqrt{6}c? I really hope I've finally got this :P
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    What is the 4-momentum of a particle with given rest mass and speed?

    Thanks. The reason I didn't use it yet is I don't know E yet. My textbook did mention that the temporal component is = E/c, is this correct? If that is true then E=2\sqrt{2}c^{2} and I can go on and (hopefully) do the rest...
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    Lagrangian Mechanics - Pulley System

    Homework Statement Here's a little diagram I whipped up in paint: http://img83.imageshack.us/img83/7625/diagramcj4.th.jpg Sorry about my sucky art skills. The wiggly line is a spring with spring constant mk and natural length d. The actual length of the spring is y. The two masses to...
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    What is the 4-momentum of a particle with given rest mass and speed?

    If the 1st part of the 4-momentum in this case is the temporal component, is the other part of the textbook correct in saying this part is = E/C and mc? and does this m refer to proper mass or relativistic mass? its not at all clear :/ If it does refer to proper mass then this would mean the...
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