The Solution right here:
dG(T,P) = dG(1,298) + I(VdP)
= 2892.3 + (-1.881 10^-6)(P-1) x (1.013 x 10^5)
The transformation is thermodynamically spontaneous at 298 K as long as dG(P,T) is negative:
2892.3 + (-1.881 x 10^-6) (P - 1) x (1.013 x 105) < 0...