doesn't seem like it'd be right either
looking at the answers
30C25 -> choose any 25 of the 30
25C4 -> all combinations of the 4 in the group of 25
so would it be 30C25 - 25C4? This isn't exactly an answer but there is 30C25 - 26C4 and 30C25 - 26C25
30C25 -> choose any 25
30-4 = 26 so 26C4...
so part 2 of this problem is
of the 25 how many groups have at least 1 calculator that needs to be recharged
so I need 1 out of the 25 + 2/25 etc
so
25C1 * 30C24 + 25C2 * 30C23 + 25C3 * 30C22 + 25C4 * 30C21
? since I'd choose 1 out of 25 to be broken then choose the remaining 24 to be OK...
so 21 blank slots 4 are accounted for already (or the combination doesn't count) in the 25 so I would need to choose 21 calculators from 26 leftover?
26C21? Thank you.
Homework Statement
There are 30 calculators and a teacher selects a group of 25 of them. 4 of them need to be recharged. How many samples of the 25 calculators contain all 4 of the calculators that need to be recharged
a. 30C4
b. 25C4
c. 30C25
d. 26C21
e. none
Homework Equations
nCr...
i(t) is discontinuous, you can't integrate it. Or at least I don't know of a way. It's discontinuous since dv/dt at the flip of the switch goes positive to negative or vice versa.