Recent content by Nick89

First of all, I don't see how having the times "as near correctly as possible" simplifies the daily drift corrections. Does it matter if you have to correct 2 nanoseconds or 2 milliseconds or even 2 years drift? It seems just as easy to me regardless of how much drift you are correcting for...

Sorry to piggyback on this thread but this is something I have been wondering about for a while and I still have not found a satisfactory answer. It is commonly said that GPS clocks are corrected for SR/GR, because otherwise they would drift away from Earth clocks by something like 38...

Nobody? :( I have gotten a little bit further I believe. I imagined the thin film being cut up into many square blocks, where each block is transformed into one particle. Therefore the volume of such a block should be equal to the volume of the particle. I called the width and length of the...

Hi, I'm trying to understand the derivation to an equation I found in the following paper: http://pubs.acs.org/doi/abs/10.1021/nn203035x I posted almost this exact question on Physics Stack Exchange but got no replies so I decided to try it here instead, I hope that's ok...

Thanks... I finally got it :) At least now I am sure that Rp is the reflectivity with the minimum. The paper I found these formulas in actually had them reversed, they stated Rs as the formula with sec theta and Rp with cos theta... I knew they were wrong, I just couldn't prove it to myself...

Thanks for your reply. I have tried this but I'm still getting nowhere. If I understand you correctly you are saying that I should approximate the square root by \sqrt{1-\left(\frac{\sin \theta}{n+ik}\right)^2} \approx 1-\frac{1}{2} \left( \frac{\sin \theta}{n+ik} \right)^2 Then use r...

Hi, I posted a similar question a while back but never got a decent answer, most probably due to having too many details that obscured the real problem. This time around I'll try it more simply. Fresnel's equation for reflectivity for s- and p-polarization are, according to Wikipedia, given...

As far as I was aware the Brewster angle is that angle where the reflectivity is zero. That doesn't apply to metals. http://ieeexplore.ieee.org/Xplore/login.jsp?url=http%3A%2F%2Fieeexplore.ieee.org%2Fiel5%2F4915369%2F5013462%2F05013535.pdf%3Farnumber%3D5013535&authDecision=-203 however seems...

Ok, I didn't see that... Thanks, that makes sense. So their equation for the TE mode comes out to what I wrote as Rp in my first post, and their equation for TM mode comes out to what I wrote as Rs (I checked it). That doesn't help my confusion though. Another optics book I have shows the TM...

How can you justify that if the page before that they set n^{^}_2 \cos \theta_2= n_2(1+i \kappa_2) \cos \theta_2 = (n_2+ik_2) \cos \theta_2 = u_2+iv_2 and then derive that 2u_2^2=n_2^2(1-\kappa_2^2)-n1_^2 \sin^2 \theta_1 + \sqrt{(n2_2(1-\kappa_2^2)-n1^2 \sin^2 \theta_1)^2 + 4n_2^4\kappa_2^2}...

Thanks for looking. I have a digital copy of that book, but I couldn't find the formulaes... I found a few that seem similar, such as \rho_{12}^2 = \frac{(n_1 \cos \theta_1 - u_2)^2 + v_2^2}{(n_1 \cos \theta_1 + u_2)^2 + v_2^2} (formula 6) but when I tried to replace u2 and v2 by the formulaes...

Sorry I can't make out what you are saying... First you say it should be the s-polarized reflectivity that has the dip (meaning I would be wrong), then you say I am correct..? So which is it according to you? And the fact that the paper is 60 years old merely means I cannot find it online where...

Thanks for the reply. At the moment I am more and more convinced that the paper has switched around the definitions for Rs and Rp. All graphs I can find of reflectivities off metals show Rp to have the dip, but when I graph Rp as it is defined in the paper it doesn't have this dip (Rs does...

Nobody? :(

Hi, I am trying to understand the reflectivity from metal surfaces, but I'm stuck... I am finding contradicting results and I can't figure out where I'm going wrong. I am reading a paper [1] about IRAS (Infrared reflection absorption spetroscopy) where an IR beam is reflected from a metal with...