Recent content by nicodemus1

When I first read the problem, I assumed that "length" meant the "length of a side". I faced the same dilemma as to what I should do in the case of a polygon which is not regular. That was another reason why I found faced difficulties accepting soroban's solution. The question following this...

Good Day. I made a mistake by not taking a closer look and working on soroban's expression. This was because I assumed that soroban considered a specific scenario only, which is squares in this case, and that it might not answer the question in general. But after Opalg's post, I believe that...

Good Day. I still have not been able to solve this question. I have not had a look at it for the past year due to other priorities. soroban's reply did not help me at all. I assumed that all n polygons are regular polygons. Therefore, the formula I used for the area was...

Good Day, I can't solve the following problem because I don't know how to find the length of the first polygon. That's why my expression for the total area has 2 variables instead of just n. Any help/ advice on how I can get an expression for the total area in terms of n will be greatly...

Yes, it is quite simple actually. I used the approach to express the given complex number in x+iy but I made a careless mistake there. Thank you very much for all your help and advice.

Good Day, I would like to know how to find the complex conjugate of the complex number 1/(1+e^(ix)). I got (1+e^(-(ix)))/(2+2 cos x) but the solution is 0.5 sec (x/2) e^(i(x/2)). Any help will be greatly appreciated. Thanks & Regards P.S. Apologies for not using LATEX as it was formatting...

Good Day, Thank you for your reply. However, I still don't get why sa + tb divides gcd(a, b). Thanks & Regards, Nicodemus

Good Day, I have to prove Bezout's Lemma. I have proven that since gcd (a, b) divides a and gcd (a, b) divides b, gcd (a, b) divides sa + tb. I've made use of the well-ordering principle and Euclid's Algorithm to show that sa + tb divides a and sa + tb divides b. What I can't prove is that...

Good Day, Thank you for the reply. However, I don't see how it simplifies to the given solution. If it does, then I would first have to divide the expression by a term, right? How do I obtain that term and division from? Thanks & Regards, Nicodemus

Good Day, My friends and I are stuck on solving the last part of the attached problem. The solution is 2^[(n^2 + n)/2] - 1. Can anyone help us with solving this? Thanks & Regards, Nicodemus

Thank you all for your advice. However, I'm not required to transform the expression into a linear equation to plot it. I have to solve for x and y. I apologise for not making myself clearer earlier. I was given 2 equations and I have to solve for x and y. The other equation is: \(64(4^y) =...

Good Day, I need some help with the following problem. I do not know how to generate a linear equation connecting y and x from the expression below as the 4 seems to complicate things \(3^y = 4(3^{x-2}) - 1\) Could some one please care to give me some advice? Thanks in advance.

Good Day, I'm sorry about this but I'm still having trouble finding the general solution for this...

Brilliant! It's crystal clear to me now. Thanks very much!

Good Day, Thank you so much for your help. However, I don't understand how you got this part: [FONT=MathJax_Main]⇒[FONT=MathJax_Main]sin[FONT=MathJax_Math]x[FONT=MathJax_Main]=[FONT=MathJax_Main]0[FONT=MathJax_Main] or...