Yes, my bad. I was confused because of the vapour pressure. So my gibbs free energies for liquid and gaseous state would be -83,71 J/mol and -78,62 J/mol. But I don't see how that could be. It's no where near the values I could find on Internet.
I don't really see the mistage I made. I took...
But if I could calculate the enthalpy and entropy under standard conditions I could calculate G = H- TS (the 8560 J/mol value). And then use the formula to calculate the vapor pressure. Or should I rather calculate using the respective volumes?
I can calculate the free energy for liquid and gaseous at 3169 Pa. Values would be -83,71 J/mol for liquid water and -78,62 for the gaseous state at 25°C and 3169. I would need to calculate these values for standard conditions
I have the enthalpy, vapor heat, volumes and entropy of water at 25°C and its respeptide vapor pressure in my steam table (3169 Pa, which I need to calculate. So I can't use this value). But I need to calculate these values for 1 atm and 25°C. Then I could calculate calculate the gibbs energy...
Homework Statement
Calculate the vapor pressure of water at 25°C, based on the Gibbs free energy when vaporising from liquid water to vapor (so at 1 atm and 25°C ).
Homework EquationsThe Attempt at a Solution
After integrating d g/d p= RT/p. I get my formula p = p0*exp (-delta gm(p0, T)/RT). I...