Recent content by nigelhowie

oh yea thanks! since work done = force x distance moved in direction of force so, X must not be calculated because if X is in, we're calculating work done. thanks! =)

nope I'm taking physics unit 1. this topic is killing me. thanks for the link anyway =) ok. so, if there is no frictional force acting on the body, so, basically, the only force acting on the object is mgxsin(theta)? F = mgxsin(theta) ?

btw, x= 30cm

ok erm.. i was thinking mgxsinθ = Frictional force x x because since the object is not moving, gravitational potential energy is equals to frictional force? please help me my edexcel exams are drawing really near. thanks

The diagram shows a smooth wooden board 30cm long. One end is raised 15cm above the other. A 100g mass is placed on the board. The two forces acting on the 100 g mass are shown in the free-body force diagram. what is the magnitude of the resultant force?