ok when i solve x, y and lagrange they want me to find this
Use the second order condition to determine if the optimal point is maximum
or minimum.
that means i take the second derivative and how do i determine if it is a max or min?
Homework Statement
Use probability trees to determine the probability of obtaining,in a deck of cards:
two red cards (A-10 hearts or diamonds) and two picture cards (any suit) in any order?
Homework Equations
The Attempt at a Solution
P(1st red card)= 20/52 P (2nd red...
Ya so the derivative are:
dL/dx= 12.25x-42+5y-L
dL/dy= 5x-28+2y-L
dL/dL=-(6x+5y-37)
You then set them to 0 so they are
dL/dx= 12.25x-42+5y-L=0
dL/dy= 5x-28+2y-L=0
dL/dL=-(6x+5y-37)=0
Then, could you times the 2nd equation there which is dL/dy by 2 to give you common y terms of 10y?
I typed out the word lagrange because i do not have the backward L function on my keyboard. It means -backward l . I know how to get the derivative now . I just don't know how to solve for x, y and lagrange(backward l)
dL/dx= 12.25x-42+5y-lagrange
dL/dy= 5x-28+2y-lagrange
dL/dL=-(6x+5y-37)
So 12.25x-42+5y-lagrange=0
5x-28+2y-lagrange=0
-(6x+5y-37)=0
What do you do next?
Multiple them by a common factor.what do you do with lagrange?
df/dx=12.25x -42 +5y
df/dy=2y-28+5x
df/dlagrange = -(6x+5y-37)
You make them all equal to 0 so
df/dx=12.25x+5y-42=0
df/dy=5x+2y-28=0
df/dlangrange=6x+5y-37=0
Is this right? then you find a common factor between the first two equations in order to solve for x and y? how do you find lagrange?
Homework Statement
A deck of cards is shuffled and a card is dealt. The remaining cards are shuffled and another card is dealt. The process is repeated until you have four cards dealt from the main pack. Use probability trees to determine the probability of obtaining:
four red cards (not...