Recent content by nimboman

hey thanks for ur help. i got it. ur from ntu aero?

this question doesn't make sense. since both weights are at the same height above the floor. when its released, the objects will move in the direction of the force provided by the 6kg weight. so the 6 kg mass will hit the ground and the 2.4kg mass will be pulled up. since the height is 0.5m...

Two objects with masses 6.00 kg and 2.40 kg hang 0.500 m above the floor from the ends of a cord 5.30m mlong passing over a frictionless pulley. Both objects start from rest. Find the maximum height reached by the 2.40kg object.

sorry if i phrased the question wrongly. the question is asking for the coefficient of the kinetic friction. so in this case we only take into account friction when the crate is moving

anyway, when the crate is moving with frictional force taken into account. the force parallel to the ramp is it mgcos59? so the frictional force is just mgcos34 - mgcos59? but now i equate this frictional force to mgsin(theta)*friction coefficient. in this case i 34 for theta or 59?

oh wait, frictonal force will actually affect the normal force. so i can't use 34 as the angle

ok i suppose i can find the force acting parallel to the ramp when the crate is not moving. which is (mass of crate + mass of me)*sin34*g. I'm not sure how to calculate the force when frictional force is taken into account. since friction is equivalent to normal force*friction coefficient, in...

i don't really know how to start. need some enlightment!

Sorry forgot to post the question. The question is what is the kinetic coefficient between the crate and the ramp

I believe the 172kg does not include the mass of the person.

A steel washer is suspended inside an empty shipping crate from a light string attached to the top of the crate. The crate slides down a long ramp that is inclined at an angle of 34degrees above the horizontal. The crate has mass 172kg. You are sitting inside the crate (with a flashlight); your...