Homework Statement
A swimmer is standing on the west bank of a river 600 m wide. The current in the river is 3.0m/s and the swimmer can swim 5.0 m/s in still water.
a) If the swimmer swims due east, what is the time it takes to get across the river?
b) What is the minimum time to get across...
Okay, so the force exerted by the electric field will be tangent to the field line, whereas the force exerted by the magnetic field will be perpendicular to the field line, but the particle is already moving in a circle...so would it continue towards the opposite charge in this circular motion...
I'm thinking that due to the force of both the electric field and the magnetic field on the charged particle, since Fe = qE, and Fm = qv x B, the particle will move faster, and in the direction of it's opposite charge?
Oh, is it that because the velocity is zero the force will also be zero...
Homework Statement
I have a couple questions from my textbook that I was looking at when studying, and since there are no answers, I'm not sure whether what I'm thinking is right.
1. A charged particle is moving in a circle in a uniform magnetic field. A uniform electric field is suddenly...
Homework Statement
There are two of the exact same masses with mass 2.0g and are attached to the ends of an insulating thread that is 0.6m in length. The two spheres are suspended by a hook in the ceiling from the centre of the thread, and the spheres are given identical electric charges and...
Homework Statement
Since a real spring has mass, if another mass was attached to it, would the spring exert a greater force on the mass and have a smaller stretch, versus if this spring was an ideal spring?
Homework Statement
Does the centripetal force equal the gravitational force?
Homework Equations
Fg = G(m1)(m2) / r^2
Fc = 4(pi^2)(m)(r) / T^2
The Attempt at a Solution
I have the mass of a satellite in geosynchronous Earth orbit. The period of Earth's orbit, and the Earth's radius and...
Okay,
So I tried again.
Here are the knowns for my question:
m = 21kg
theta = 40 degrees to the horizontal
coefficient of kinetic friction = 0.2
- constant speed
Applied force = ?
After a bunch of work...
Fa = 46 N
Is this correct?? That to move this block at a constant speed with those...
Ff = (Fn)(coefficient of kinetic friction)
I think my problem is putting it all together :S
Some of my equations will have too many unknowns...sometimes I have one unknown but it cancels out and the equation becomes useless...
I know that
(I have theta)..
Fa(x) = Fa(cos)(theta)
Fa(y) = Fa(sin)(theta)
Ff = (Fn)(coefficient of kinetic friction)
Fg = 9.8m (I have m)
Fn = mg - Fa(y)
So
Fn + Fa(y component) - mg = 0
and
Ff - Fa(x component) = 0
?
My unknowns are Fn, all components of the applied force, and the frictional force (but I do have the coefficient of kinetic friction).
The net force is zero.
So the applied force equals the frictional force..
But is it that the horizontal component of the applied force equals the frictional force, or the net applied force equals the frictional force?