Recent content by Nirmal

Yes. That was the mistake. Now i realize. Thank you

Can you help me ..

But 12v/7d is not the correct answer.. I checked it and i got wrong. So what can be the answer.

So will the answer be w=12v/7d

But the rod is pivoting at end of rod not at the centre of mass.

MV + 0 = 0 + I w So here I = Md^2 /3 If a ball is sticked to the end of rod then I becomes Md^2 /3 + Md^2/4 = 7Md^2/12 So solving we get w = 12v/(7d^2)

Ok is the answer w = 12v/(7d^2) or is it 3v/d^2

So how would i do that.. angular momentum of a ball moving in a straight line is zero right. SO is the answer of w = o . Is that right. Or if i am wrong please help me.

Homework Statement To understand the question first see the attachment (picture). The ball hits the rod and then it sticks to the end opposite the pivot. So now what is the angular velocity (ω) just after collision. Homework Equations 1/2m_1v_1^2 + 1/2 I_1ω_1^2 = 1/2mv^2 + 1/2 Iω^2...