i think force F on the mass2 will stretch the spring to the right side of the block of mass1 therefore block of mass 1 will have a tension force kx due to the spring so in order to move the mass spring force will have to apply force equal to or greater to Dm1g therefore kx> or equal to Dm1g so...
I took the blocks and spring as one system and calculated acceleration on each box a=F-D(m1+m2)g/(m1+m2) then i tried to solve it from a non inertial frame with a a psuedo force on mass m1 and used conservation of energy i tried this but no answer instead i found maximum elongation in the...
ok spring force required to move the mass m1 will be kx greater than or equal to Dm1g .now after drawing the free body diagram of mass 2 i have got F-Dm2g-kx=m2a (here a is the acceleration of mass 2).now if i put the value of kx from equation 2 to equation 1 i am getting the answer with m2a in...
[b]1. Two masses of m1 and m2 is connected by a massless undeformed spring rest on a horizontal plane.Find the minimum constant force Fmin that has to be applied on m2 so that other block get shifted if D is the coefficient of friction between blocks and surface
[b]2. Homework Equations...