Recent content by nivekious
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Graduate General Solution to Linear, Homogenius, Second-Order Differential Equation
I need to solve d/dx(e^(-(x^2))*(du/dx))=u+x*(du/dx) I get e^(-(x^2))*u''-2xe^(-(x^2))*u'=u+x*u' u''-2x*u'=e^(x^2)*u+xe^(x^2)*u' u''+(2x-xe^(x^2))*u'-e^(x^2)*u=0 but I have no idea how to approach the problem from here. Can somebody please help?- nivekious
- Thread
- Differential Differential equation General General solution Linear
- Replies: 3
- Forum: Differential Equations
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Undergrad Parametrizing Paths: Learn How to Do It for Functions of Multiple Variables
I'm trying to figure out what is meant by parametrizing a path, and how it would be done for a function of multiple variables. Can someone help me? -
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Multivariable Calculus Gradient-based question
I think that that's pretty much what he wants. I asked him in class the other day and I think he said it could be done by solving dy/dx=(dy/dt)/(dx/dt) but I'm not sure how to get to the parametric equations with more than one variable in the partials- nivekious
- Post #5
- Forum: Calculus and Beyond Homework Help
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Multivariable Calculus Gradient-based question
Well, I know that the gradient will give me the gradient at that point, but I need to find the curve that will be followed continually moving along the gradient at any point. I'm not sure what you mean by f(x+vt) (it may just be that this is something we haven't covered yet in class. It's an...- nivekious
- Post #3
- Forum: Calculus and Beyond Homework Help
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Multivariable Calculus Gradient-based question
Homework Statement Find the steepest path up a hill as an expression in terms of x and y whose height is given by f(x,y)=x^2y-2xy+5 starting at (2,1) 2. The attempt at a solution I know that I need to get a set of parametric equations for x and y because I have done problems sort of...- nivekious
- Thread
- Calculus Multivariable Multivariable calculus
- Replies: 6
- Forum: Calculus and Beyond Homework Help