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niz73
Recent content by niz73
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Challenging Integral: Solving ∫ [x(8-x^3)^1/3] dx from 0 to 2
I have substituted u^3 = 8 - x^3 then 3 u^2 du = - 3 x^2 dx But now the problem has only x so in order to substitute for dx I have to divide and multiply by x and that means I can not eliminate cube root.
niz73
Post #3
Nov 24, 2009
Forum:
Calculus and Beyond Homework Help
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Challenging Integral: Solving ∫ [x(8-x^3)^1/3] dx from 0 to 2
Hi all, Can you guys please help me with the following integration problem 2 ∫ [x (8-x3)^1/3 ] dx 0 Thanks in advance.
niz73
Thread
Nov 24, 2009
Integral
Replies: 2
Forum:
Calculus and Beyond Homework Help
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