nah
Nah..
I think the answer is R/sqrt2...because you have x^2 = (R/2)^2 +(R/2)^2 and that is simply x^2 =(2R^2/4) and then x^2=R^2/2....so x=R/sqrt2
:)
I've hot two assignments to do in pascal and i have no idea how to make it :(
i dont even have anything similar and i dont have time to search the web for answers now
I really need help and i need it as fast as it can be so please if anyone can help me with this i would really reallllyyy...
hm
Not really :frown:
the task...as so on my exam..they strictly want it with fourier ...
bcs we do also taylor..and in task they mention which one they want..
Well hmm...not really :rolleyes:
I did get almoust correct answer BUT...
you see b_n is zero but a_n is not...and this is where i stuck ...i cant get correct a_n
by the way...can you tell me is this true?
cos(npi) + cos(0pi) = (-1)^(n+1)
thanx again :smile:
Well first thing i always do is when i have any function given like this is to rationalize it ..meaning multiply all of this with (x+sqrt(x+2))/(x+sqrt(x+2))
You will get then this sqrt up...
(x+sqrt(x+2)) / ((x^2)-x-2)
then you have (x+sqrt(x+2)) / (x-2)(x+1)
Then you can simply seperate...
Hi!!
I had exam today and i got one task that i am not sure how i should have made it so i hope you can help me with this one
It goes :
Find the line integral (i'm not good with using symbols so i'll do my best here)
integral by line C from (y-z)dx+(z-x)dy+(x-y)dz
int_C (...