Recent content by nizama

nah Nah.. I think the answer is R/sqrt2...because you have x^2 = (R/2)^2 +(R/2)^2 and that is simply x^2 =(2R^2/4) and then x^2=R^2/2...so x=R/sqrt2 :)

I've hot two assignments to do in pascal and i have no idea how to make it :( i don't even have anything similar and i don't have time to search the web for answers now I really need help and i need it as fast as it can be so please if anyone can help me with this i would really reallllyyy...

hm Not really :frown: the task...as so on my exam..they strictly want it with Fourier ... bcs we do also taylor..and in task they mention which one they want..

aha Yes i just got it.. it is when you use integr. in series so then it would be ((-1)^n +1) thanx :smile:

Well hmm...not really :rolleyes: I did get almoust correct answer BUT... you see b_n is zero but a_n is not...and this is where i stuck ...i can't get correct a_n by the way...can you tell me is this true? cos(npi) + cos(0pi) = (-1)^(n+1) thanx again :smile:

Hi there! Can anyone please help me with this one..? Find the Fourier Sine series of f(x)=sin(x/2) for interval (0,pi) thanx a lot :)

Well first thing i always do is when i have any function given like this is to rationalize it ..meaning multiply all of this with (x+sqrt(x+2))/(x+sqrt(x+2)) You will get then this sqrt up... (x+sqrt(x+2)) / ((x^2)-x-2) then you have (x+sqrt(x+2)) / (x-2)(x+1) Then you can simply separate...

Thank you so much i will try to work from there :)

Hi! I had exam today and i got one task that i am not sure how i should have made it so i hope you can help me with this one It goes : Find the line integral (i'm not good with using symbols so i'll do my best here) integral by line C from (y-z)dx+(z-x)dy+(x-y)dz int_C (...