Recent content by Noah Drakes

V= ∫t0 t1 (A/m) (r(t))4/3

and of the initial value of r(t) is 500

where t1 = 10 and t0 is 0

Ok, I think i Got it So the equation for velocity when acceleration varies from t0 to t1 is V=∫t0 t1 (A/m) (r(t)) 3/4

∫t0t1 = u + a * (t1 - t0) da

time

∫t0 t1(v-t)/u

i feel stupid. i know this isn't a hard problem. i feel like I am wasting your time

V = (u) + (a * t) ?

To find the velocity you would take the integral of a (V = ∫ a(t) ) then plug t1 into the equation for V. the max velocity occurs when a = 0

and why am i integrating, to get the maximum velocity ?

Ok so if r(t) stays constant, and the initial value for r(t) is 500 ffu, then i should integrate the equation (A/m) * 5004/3. but would i integrate with respect to A or m ?

Haha whoops.

But this doesn't seem right. The jets' fuel consumption would never stay constant during an acceleration period. Am i misinterpreting the meaning of (r(t))?

Ok i understand. The differences between each statement is the state of (r(t)). It is either constant, increasing, or decreasing. So that implies i would have to manipulate the value of (r(t)). When (r(t)) is constant its value remains at 500. When the rate is decreasing steadily, however, i...