Recent content by noboost4you

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    Axially Loaded Member and Tensile Stress oh so lost

    Wow, well I expected that to be worse. Thank you very much
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    Axially Loaded Member and Tensile Stress oh so lost

    normal stress of section 1 = 1590N / 0.15m^2 = 10600 N/m^2 normal stress of section 2 = 1590N / 0.05m^2 = 31800 N/m^2 Could it be that easy? Feel like I'm missing something still
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    Axially Loaded Member and Tensile Stress oh so lost

    Those above areas should read m^2 and not just meters.
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    Axially Loaded Member and Tensile Stress oh so lost

    Area of a rectangle is length * width So at section 1, the area A would be 30mm*5mm = 150mm = 0.15m ? and Section 2, the area A would be 10mm*5mm = 50mm = 0.05m ? Then I would just plug those areas into the normal stress = P/A equation for both sections? Thanks for the quick reply
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    Axially Loaded Member and Tensile Stress oh so lost

    Homework Statement "The axial load for a given test sample carries 1590 N. Calculate tensile stress at sections (1) and (2) assuming the sample thickness is 5mm. (Rectangular cross section). http://img208.imageshack.us/img208/121/tensilestressby1.th.jpg [Broken] Homework Equations...
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    Statically Indeterminate Stepped Bar Problem

    Ah excellent! Thank you very much. The equations for Ra and Rb were a little more complicated but I got the answers the back of the book has. I'm surprised I didn't see that I was cancelling out both A's when they clearly aren't equal to each other. Thank you very much. This forum has...
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    Statically Indeterminate Stepped Bar Problem

    I didn't assume the cross-sectional areas were the same. The fat piece is 6 in^2 and the skinnier piece is 3 in^2. In my thinking: Stress of AC should = 44.44 kips/6 in^2 = 7.41 and Stress of BC should = 55.56 kips/3 in^2 = 18.52 However those are not the answers. In the back of the...
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    Statically Indeterminate Stepped Bar Problem

    I've been having difficulty with this problem for the past 5 hours. I am understanding some part, but I can't get the final answer. http://img223.imageshack.us/img223/1103/1015zz1.th.jpg [Broken] This is what I got so far: EFx = Ra + Rb - P = 0 Ra + Rb = P Sab = Sac + Scb =...
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    Equilibrium of Coplanar Force Systems HW Problem

    I'm not following "make a cut through the cable" part? Thanks
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    Equilibrium of Coplanar Force Systems HW Problem

    No, but you're close. T = 143 N, Ax = 71.5 N to the left, and Ay = 464 N up
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    Equilibrium of Coplanar Force Systems HW Problem

    I would love to say that that information was helpful, but it just made me more confused. Does it matter that the rope is at an angle?
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    Equilibrium of Coplanar Force Systems HW Problem

    Says it attached and I can access it by clicking on it, but I uploaded it elsewhere as well. http://img265.imageshack.us/img265/5564/363no0.th.jpg [Broken]
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    Equilibrium of Coplanar Force Systems HW Problem

    Anyone have any suggestions? Really scraping the bottom of the barrel here. Thanks
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    Equilibrium of Coplanar Force Systems HW Problem

    I've been having trouble with the homework problem attached as an image. I need to find the tension in the cable and the reactions at A (Ay and Ax). In previous homeworks, I've been able to find the reactions at similar points A by finding the moment about A around a few other points. Now...
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    Specific Heat of aluminum Problem

    Am I in the right ballpark with what I have written above?
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