Recent content by nolee52738

I have tried this now: (1)m(1.30-u1) = M(u2-1.30) (2)m(1.69-u1^2) = M(u2^2 - 1.69) (2)/(1) --> (1.69-u1^2)/(1.30-u1) = (u2^2 -1.69)/(u2-1.30) (1.30-u1)(1.30+u1)/(1.30-u1)= (u2-1.30)(u2+1.30)/(u2-1.30) 1.30+u1 = u2 +1.30 u1=u2 ??

*mass of the ball= m mass of the bat= M *speed of the ball after the collision= u1 speed of the bat after the collision= u2 *speed of the ball before the collision= v1= 1.30m/s speed of the bat before the collision=v2= 1.30 m/s *mv1 + Mv2 = mu1 + Mu2 1.30m + 1.30M = mu1 + Mu2...

Hi, Can anyone help me in this question? 1) A ball and bat, approach one another each with the same speed of 1.30 m/s, collide. Find the speed of the ball after the collision. (Assume the mass of the bat is much much larger than the mass of the ball and that this is an elastic collision with...