Yes I have read it, which is why I responded with what I did, though I did not completely understand what was meant by it. The question wants me to sketch it, so if the equation has no real roots and doesn't cross the x-axis, how is that possible? Just plug in x-values to the original equation?
So assuming I do not need the square roots, then the vertex must be (3, -5) and the y-intercept must be 9? Given the equations I have, it seems like they are the only possible values. However, when using a function graphing tool the y-intercept doesn't appear to be 9, nor does the vertex look...
I'm not sure the relevance (if any) of finding the roots. I saw it done in a video, and since the question wants a sketch of the graph, I assumed that I would be needing two values (x and y) for the vertex, hence the need for two roots. Sorry about the screw-up on the equation - I usually do a...
Hi,
I am having trouble with completing the square in this question. I've looked at several online videos and I am still confused as to why I am not getting an answer that makes sense. I keep ending up with complex numbers and I am not sure what the next step to take is.
Homework...
Hello,
For this question I managed to find an answer but I am not sure if what the question means is to plug in the x-value and find the slope, or first find the derivative of the function, and THEN solve for the slope using f'(x)=10x+5h-2 (what I got for the derivative of the function). If...
Hello again,
I am having trouble with a particular limit problem and would appreciate any help/pointers you can offer. The question is asking for the nth term of the sequence 2, \frac{3}{2}, \frac{4}{3}, \frac{5}{4}
.. and also asks for a limit of the sequence. My immediate guess was to apply...
Hello, I am struggling with limits in my calculus course and would appreciate a bit of help. The question is:
\lim_{x→-6}\frac{x^2-8x+12}{x^2-x+30}
So far I have tried the factoring and substitution methods but have not managed to match the answers given by online equation solvers. For...