Recent content by NonAbelian

  1. N

    Basic: Properties of ln & Exponents

    I really don't understand why you keep saying there is no unknown. i is the rate of interest, which is the unknown variable. I don't know how I can make it plainer than that?
  2. N

    Basic: Properties of ln & Exponents

    Ouch, I wasn't expecting that, ugg! For (a) what I meant was to make 5(1+i)^8 + 10(1+i)^4 = 3 into a quadratic in x=(1+i)4 so: 5x2+10x - 3 = 0. The numbers are not correct, but the form is. Thanks for your reply.
  3. N

    Basic: Properties of ln & Exponents

    So what is ln(a+b) equal to in terms of ln(a) & ln(b)?
  4. N

    Basic: Properties of ln & Exponents

    Homework Statement I'm taking a math of investment and credit course, in this case, solving for i which is the interest rate. My question is: is it possible to "ln both sides" of an equation? Like in (b) below, I know I could say y*ln(1+i) = ln(3). Homework Equations (a) 5(1+i)^8 +...
  5. N

    Find the derivative of F(x) = (8x^3 - 1)/(2x - 1), is this right?

    try this instead: (regard this as long division, not a square root!) 2x-1 \sqrt{8x^3+0x^2+0x-1} And remember, whatever you get in the end, your derivative has a discontinuity at x=1/2!
  6. N

    Finding the Derivative of a Function Given an Equation and Initial Condition

    And don't forget to use the chain rule on the second part. You'll end up with an equation that involves both f(x) and f'(x). At this point, sub in x=1 and f(1)=2 and solve for f'(x).
  7. N

    Answer Quadratic Implicit Function: Horizontal/Vertical Tangent Line

    If the question is supposed to be x²+y²-4x+7y = 15 then I believe that your answer for y' is incorrect. Note that your original equation is that of a circle which has been shifted. To write it in standard form, (x-a)²+(y-b)²=c² you can complete the square (I'm getting to a nice geometrical...
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