∆KE = 1/2mV(final)² - 1/2mV(initial)² ?
∆PE = mg∆h
∆EE is N/A
∆KE + ∆PE = 0
∆PE = 110kg x 9.81 x 7.6m
=8201.16
.·. Should ∆KE = -8201.16 ?
V(initial) = 0
∆KE = 0 - 1/2mV(final)²
V(final) = √(2x∆KE/ -m)
V(final) = 12.2114... m/s
at the end of the angular part of slide...
Homework Statement
A waterslide ride consists of a straight guided ramp, at an angle theta (to the horizontal plane), with a transition to a short horizontal section at the bottom of the slide (1m long), just above the surface of a splace pool of length L. Patrons queue on a platform of...