Recent content by NoobertNoClue

∆KE = 1/2mV(final)² - 1/2mV(initial)² ? ∆PE = mg∆h ∆EE is N/A ∆KE + ∆PE = 0 ∆PE = 110kg x 9.81 x 7.6m =8201.16 .·. Should ∆KE = -8201.16 ? V(initial) = 0 ∆KE = 0 - 1/2mV(final)² V(final) = √(2x∆KE/ -m) V(final) = 12.2114... m/s at the end of the angular part of slide...

Homework Statement A waterslide ride consists of a straight guided ramp, at an angle theta (to the horizontal plane), with a transition to a short horizontal section at the bottom of the slide (1m long), just above the surface of a splace pool of length L. Patrons queue on a platform of...