I'm having difficulty time of trying to figure out answer.
Question:
P(A^c U B) = 0.6
P((A^c U B^C) = 0.8
Find P(A) ?
Sol:
P(A^c U B) = P(A^c) + P(B) - P(A^c Intersection B)
P(A^c U B^c) = P(A^c) + P(B^c) - P(A^c Intersection B^c)
0.6 + 0.8 = 2*P(A^c) + 1 - P(A^c) <==== HOW ?
P(A^c)=0.4...
umm...
ex) for 4 digits
negative = 1000
positive = 0000
I guess 5 is a easy small number to make to binary
3210
-----
0101
is this right ?
so for Sign/Magnitude
1101 = -5
is this right ?
if this is right. how to convert this to Two's complement ?
1. I kinda get it. but how did you get these calculations ?
(2F = 2*16 + 15*1) and (1B = 1*36 + 11*1).
2. How do you convert decimal to character ?
3. How did you get (2 and F) and (1 and B) ?
Java help ! (how to not to use if statement)
My teacher asked the user for an integer and converted it into a number in base N, where N was a value between 2 and 9, inclusive. Expand this program to allow values of N between 2 and 36, inclusive, where digits representing the numbers 10, 11...
so 2048 bytes = 16384 bits
since 4mb of a square matrix(meaning it has two cells ?)
16384 bits = 16384 rows
16384 bits = 16384 columns
How about #4 ?
Since it is asking for maximum memory size of the machine, would it be 2^40-1 ?
What is the maximum number of distinct operations that this...
so would 16-bit cells of memory in sign/magnitude notation with largest absolute value is 0,111,111,111,111,111 right ?
but it's asking for 1 memory cell and 2 memory cell.
So how should I answer it ?
One memory cell : It is simply asking for one's complement ?
Two memory cells : It is...
You mean with positive 3 digits.
0 000
1 001
2 010
3 011
You mean with negative 3 digits.
-0 100
-1 101
-2 110
-3 111
But I don't know how to get with 16 digits.
Can you show me how with examples with 4 digits, 8 digits ?
Can you guys please show me how to calculate with details ?
I have no clue how to do it, and where to start ?
I'm an international student and I really don't understand.
Thank you.
1. Suppose that we have a memory system with 16-bit cells of memory. If we use sign/magnitude notation to...