Recent content by NoWay1

This must be the answer I needed, thank you

Thanks a lot for the confirmation, way the question was presented was very confusing to me, as if they had to have the same antideravative

So I have to show 2sin^2(x) and -cos(2x) have the same antiderative. Here's how I approached this. 2sin^2(x) = 1-cos2x ==> u = 2x intergral of that is (u - sinu)/2 + c = x - (sinx)/2 + c -cos2x ==> u = 2x intregal of that is (-sinu)/2 + c= -(sin2x)/2 + c Have I calculated/approached this...

Wow, this is the first time I see a whole quadrant being in the graph, I would never have figured that out myself, thanks a lot for your clear explanation!

The equation is x-|x|=y-|y| and I need to make a graph for it. So I thought I should solve it by breaking it down to 4 different equations, which would be - x - x = y - y => 0=0 x - x = y + y => 0=2y => y = 0 x + x = y - y => 2x=0 => x = 0 x + x = y + y => 2x=2y => x = y But this isn't...