Firsly, if there has been no rotation in the non-reference frame the equation would have been like this, I call it as an accelerated reference frame (remember no rotating),
m\boldsymbol{\ddot{r}}=\boldsymbol{F}-m\boldsymbol{\ddot{R}}_{0}
which is very easy to interprete this equation. This is...
So you mean that my "guessing" interpretations about the second and third terms were right? I understand you very well about the calling the forces as "fictitious" forces. Since the laws of Newtons belong to the inertial reference frame, then socalled “forces” outside the inertial reference...
Hello. Before I ask a question I want you to remind that it is my first time to use this page. And I am not even good at speaking english. My question is about the fictitious forces. I have made a long proof for the formula of the force in the non-inertial reference frame with the second law of...