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N
Pleace, "explicit math" would help..
If you know it:-D
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N
Yes "add one" and then I square which makes the equation:
(Z+1)^2=(1+v/c)/(1-v/c)
but how do I then rewrite it?
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N
Thank you for this posting but may i please ask for the algebra steps from:
Z=(sqr(1+v/c)/(1-v/c))-1 to,
v/c=((z+1)^2-1)/((z+1)^2+1)