Recent content by nubmathie
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Graduate Complete Norm on M_n(R): Questions & Hints
Would you know how to show that ||AB||*<=||A||*||B||*? This would be helpful for Problem 2. Also, how is ||B||* equal to sup{||B'(x)||: ||x||=1}? Notice that in my definition of || ||*, X refers to an nxn matrix.- nubmathie
- Post #4
- Forum: Differential Geometry
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Graduate Complete Norm on M_n(R): Questions & Hints
Let M_n(R) be the n x n matrices over the reals R. Define a norm || || on M_n(R) by ||A||= sum of absolute values of all the entries of A. Further define a new norm || ||* by ||A||* = sup{||AX||/||X||, ||X||!=0}. Show that 1. M_n(R) under || ||* is complete. 2. If ||A||<1, then I-A is...- nubmathie
- Thread
- Banach Matrix Space
- Replies: 3
- Forum: Differential Geometry
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Graduate Challenging Problem (Equivalent Metrics)
I assume it is not TOTALLY bounded by Heine-Borel. Not compact=> not complete or not totally bounded. If not complete, then we are done. Therefore assume not totally bounded but complete.- nubmathie
- Post #6
- Forum: Differential Geometry
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Graduate Challenging Problem (Equivalent Metrics)
OK here is an example. Take the set of the natural numbers. Under the usual metric p it is non-compact. But now I can define a new metric p* by p*(n,n)=0 and p*(n,n+1)=1/2^n. It is easy to check that p and p* are equivalent. Further, the sequence {n} used to be unbounded under p, but it is now a...- nubmathie
- Post #4
- Forum: Differential Geometry
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Graduate Challenging Problem (Equivalent Metrics)
Challenging Problem! (Equivalent Metrics) I need to show that if (X,p) is a non-compact metric space, then there exists a metric p* equivalent to p such that (X,p*) is not complete. I greatly appreciate your help!- nubmathie
- Thread
- Replies: 10
- Forum: Differential Geometry