the d(difference) is 1/(365* 100*60*60). If your value for n= x*365*100(where x is the value of centuries).
Thanks Dick. The answer is 2.92 cumulative hours. (This was an interesting question)
its changing the difference per day at the end of the centuary changing.
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rate at which the time is changing is the difference per day. I don't know what...
Well you need to use arithematic sequence and I got 2.81 hours total change at the end of the given tine. Maybe I understood the question wrong. Sn= n/2(2a+(n-1)d)
n=24*365*100
a=1
d=1(i think i am not sure)
Please help.
Thanks.
Very hot question(Answering will get you 5 dollars, just kidding.
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Well ofcourse even though its a waste of me time why not. :smile:
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