Recent content by Numeriprimi

B) The orbuital period of the particles is different... I can calculate it by orbital speed: v = √(G*M_S/R) So, the particles 74 658 km from center of Saturn: v_1 = 22 527 m/s - period: P_1 = 2*74 658 000*3,14/22 527 s = 20 813 s = 5, 78 h particles 92 000 km from center of Saturn: v_2 = 20...

So, I have some solution of C. Pls, tell if it is good. τ = N/V *σ*l τ = 0,1 (by B) N = ? (total number of particles in ring)... N/N_A = M/M_H2O, so N = M/M_H2O * N_A (can I say this?) V = m/ρ σ = R^2 * ∏ l = WHAT is l? it is 92 000 km-74 658 km? Or I have to say that: l = V/ (92 000^2 * 3,14 -...

Yeah, I understand the first paragraph. Hm. So, with disk particles... 10 %? (like the optical depth?). I don't know. However, how can I determine the time of collision by this?

Yeah, I calculated it :-) Thank you very much, it is everything.

I'm standing on Earth and watching on the Moon (-13 mag) - I'm seeing the ashen light of Moon (-3 mag). opposite situation: I'm standing on Moon and watching on the Earth (-16 mag, no lighting by people) - I'm seeing the ashen light of Earth. How can I determine the magnitude of ashen light by...

How do you know it? From which law? there is a assumption that a one particle orbit in a circle outside of the ring plane with really small inclination Twice? Why twice? Hmm. The collision have to be, so 100 %?so, the σ = R^2 * ∏; where R is what in this example? it is the radius of particle?

A: Ok, I checked it and it looks good. B: Broken grammar? Emh. So, I try to write it better. Assume that a one particle orbit in a circle outside of the ring plane. Calculate the time in which will be collision with a particle of ring. Calculate it for ring C between 74 658 km and 92 000 km...

one more question... is also any way, how to determine the ashen light of Earth? no light of buildings etc., only the ashen light like on Moon.

Ok, I understand. Thank you very much! Hmm... And if I will know the magnitude of full Earth and full Moon and the ratio between radius of Earth and radius of Moon, I can determine the radius betwenn albedo of Earth and albedo of Moon, yeah? 2,5 log ((r_E/r_M)^2 * A_E/A_M) = 2,5 log...

Homework Statement Hello. I have this examples about Saturn: A) Calculate the radius of the inner edge of the Cassini division, if you know that this sharp transition in the density of the rings is caused by a 2:1 orbital resonance with the moon ring particles with a moon Mimas, which around...

Yes, the first soulution I know. I can say that: (r_2/r_1)^2 * A_1/A_2 = I_1/I_2 ... And than I can numericated the magnitude of Earth from Moon by Pogson's equation. However, what with the ashen lights? How can I numericate the magnitude of Earth on Moon by this? I really don't know.

No. One more question. Can I determine the magnitude of Earth on Moon, if I will be know magnitude of ashen lights by Moon and Earth?

Hmm, however, how do you know that the full Earth is 43 times brigter than full Moon?

Hello, I was wondering that I'm a astronaut on Moon and I thought about a one question... If I look at the Earth (in "full moon") from the Moon, what magnitude will have the Earth? Ok, I know some typical values that the magnitude of Moon from Earth is -13 mag and the magnitude of Sun from...

the adress http://fyzikalniolympiada.cz/archiv/55/fo55a1_z.pdf