Recent content by nw0rbrolyat
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Charge and Potential Difference on 2 Capacitors
Im not sure if I have the right equations here. I am totally clueless on this problem- nw0rbrolyat
- Post #3
- Forum: Introductory Physics Homework Help
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Help! Calculating Capacitance from Voltage & Charge
I don't think I am following you. Use which equation? I did x(99)=(x+21)(127) and got -95.25 I used C=QV- nw0rbrolyat
- Post #3
- Forum: Introductory Physics Homework Help
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Charge and Potential Difference on 2 Capacitors
Homework Statement A C_1 = 2.40 \mu(micro) F capacitor is charged to 861 V and a C_2 = 6.40 \mu(micro) F capacitor is charged to 662 V. These capacitors are then disconnected from their batteries. Next the positive plates are connected to each other and the negative plates are connected to...- nw0rbrolyat
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- Capacitors Charge Difference Potential Potential difference
- Replies: 4
- Forum: Introductory Physics Homework Help
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Help! Calculating Capacitance from Voltage & Charge
Capacitance (Please Help!) Homework Statement The charge on a capacitor increases by 21 \mu(micro) C when the voltage across it increases from 99 V to 127 V. What is the capacitance of the capacitor?Homework Equations There is Q=cV, or C=Q/v. But there are 2 unknowns and no number for the...- nw0rbrolyat
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- Capacitance Charge Voltage
- Replies: 4
- Forum: Introductory Physics Homework Help
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Net Electric Field at Point P Due to Fixed Charges
http://edugen.wiley.com/edugen/courses/crs1650/art/qb/qu/c22/fig22_31.gif that is the figure they give with the problem. You can see what d is with this. You are probably correct about the meters its been a while since I have worked with SI prefixes.- nw0rbrolyat
- Post #5
- Forum: Introductory Physics Homework Help
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Net Electric Field at Point P Due to Fixed Charges
for q1 the equation I would use is E1=(8.99e9)(3e/(.0067m)^2). Do I have this setup correctly? I am not quite sure what to do with the e's will an e remain in the answer?- nw0rbrolyat
- Post #3
- Forum: Introductory Physics Homework Help
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Net Electric Field at Point P Due to Fixed Charges
Homework Statement four particles are fixed in place and have charges q1 = q2 = 3e, q3 = 7e, and q4 = -28e. Distance d = 6.7 µm. What is the magnitude of the net electric field at point P due to the particles? Homework Equations Im not sure what form of the magnitude equation to use for...- nw0rbrolyat
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- Electric Electric field Field Net
- Replies: 5
- Forum: Introductory Physics Homework Help