Recent content by Ocsycleen

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    Angular momentum of a bullet problem

    Ok yea. i think i did a little miscalculation and converted my final answer to rpm instead. Thanks for the help.
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    Angular momentum of a bullet problem

    So the left hand side of the equation should be R⊥ * P = IDisk * ωFinal But is there something else i am missing here?
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    Angular momentum of a bullet problem

    Oh it's 5cm
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    Angular momentum of a bullet problem

    is it 10cm?
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    Angular momentum of a bullet problem

    L = P * RB
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    Angular momentum of a bullet problem

    RB = sin(θA) * RA
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    Angular momentum of a bullet problem

    sin(180-θA) = RB / RA
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    Angular momentum of a bullet problem

    Because the disk is stationary before the bullet hits so right before the moment of impact, the only thing angular momentum that should exist should be for the bullet which is the cross product of r and p.
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    Angular momentum of a bullet problem

    Thanks. I did not include the bullet's contribution to the inertia because the problem said to Ignore the mass of the bullet after it hits the disk. I am still confused about how the 5cm above the rotation axis should be used in this problem.
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    Angular momentum of a bullet problem

    Homework Statement A 4 g bullet traveling at 500 m/s strikes a disk of mass 1 kg and radius 10 cm that is free to rotate around an axis passing through its center. The bullet’s incoming path is 5 cm above the rotation axis and the bullet comes to rest in the position shown in the figure. At how...