Recent content by oggrol

Teacher posted solutions today... had Jz=Pv*Vx ... Still don't believe that though unless it was a misprint in the book or something ... doesn't make sense to me

Still not sure about part b of this one, and running into more problems with the stuff :cry:

Let E=Eo (err...free space, not sure how to represent the symbols) V=90z^(4/3) in the region z=0(Potential) a) Find expressions for E,D and pv (volume charge density) as functions of z My work: E=-div V=0+0)120z^(1/3)az=120z^(1/3)az V/m D=Eo E=1.062z^(1/3)az nC/m^2 pv=div D=.354/z^(2/3)...