Recent content by ollyfinn

Thanks for your help. Am I correct in thinking that values for A and B should be solved using simultaneous equations? Then they will form part of particular solution part of the final answer? Sorry if I am just not getting it. I think I may be well out of my depth at this level of study...

You are right my parentheses does need to be clearer. My final answer should be: x(t) = 1/9(t^2) + C1/3(t^-1) Does that look better?

I have the following two questions to solve Problem 1. 3x' + 1/t x = t and Problem 2. x' + 1/t x = ln t I have followed a method detailed in my textbook to try and get an answer for Problem 1 but am a bit unsure so if anyone can clarify my workings below before I spend time...

ehild, Can you see where I may have gone wrong in my method then? Cheers

ehild This was the method used to get the solution I came to: Find the general solution of x'' + 2x' + x = 3cos2t + sin2t Corresponding unforced x'' + 2x' + x = 0 Using the characteristic equation m^2 + 2m + 1 = 0 m = -1 So the corresponding equation will be xc(t) =...

Thanks ehild. I had the correct layout of the solution to Problem 2 in my notes but just made an error typing it on here so it looked like I was only taking the square root of the 2. Will have another look at my solution to Problem 1. Thanks.

Hi ehild, My typing mistake, it should read: x'' + 2x' + x = 3cost2t + sin2t

Should the final answer be y = e^(0.25x^4 - 0.667x^3/2)

I have been looking at this problem again and have come to a solution of: x(t) = Ae^-1t + Bte^-1t + 3/4t sin 2t - 1/4t cos 2t If anybody thinks this is correct then let me know. Thanks.

Will have another look at first problem. Is it just my transformation to separate y from ln [y] where I have gone wrong? The bracketed term in the second one is meant to be all under the radical. Thanks for your help.

I am trying to solve the following problem and am a bit lost so any advice would be welcomed. x'' = 2x' + x = 3cos2t + sin2t My understanding is that I need to find the general solution for the unforced equation and a particular solution of the above equation. When these are added together...

Hi I have not studied calculus for a while and I am just seeking some clarification on the following two problems I have attempted to solve. PROBLEM 1 dy/dx = y(x^3 - √x) I have separated the variables as follows: Rewrote equation as dy/dx = y(x^3 - x^1/2) Divided both sides by...

Aah that's it! Thank you very much for your help.

Hi, I too am trying to solve the second of your problems. I have used the characteristic equation to find ou that m = 2 I have then used the general solution: x(t) = Ae^m0t + Bte^m0t This has given me the following: x(0) = Ae^2t + Bte^2t = 1 Ae^2(0) + B(0)e^2(0) = 1 A(1)...