Recent content by Omanlew

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    Solving the Solar Power Puzzle in the US

    let me check this i got 9.07x10^12 m^2 for the area in meters squared for part a, I multiply 9.07x10^12(180w) and get 1.63e15 rounded? for part b do I do 1300w/18w?
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    Solving the Solar Power Puzzle in the US

    idk I am getting really frusturated with this, I've been at this for hours and have gotten no where, IM LOSING MY MIND I HATE THIS!
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    Cyclist of 80kg: Descending 3.4 degree Hill at 9.0 or 30 km/hr?

    A bicylcist of mass 80 kg (including the bike) can coast down a 3.4 deg hill at a steady speed of 9.0 km/hr. Pumping hard, the cyclist can descend the hill at a speed of 30 km/hr. Using the same power, at what speed can the cyclist climb the same hill? Assume the force of air resitance is...
  4. O

    Solving the Solar Power Puzzle in the US

    Alright I converted 3500000mi^2 into 9.07m^2 and then did (9.07m^2)(180w) and reached 1632.6w/m^2? For part b do you do .10(180w) then multiply that by 1300W and then take 305 million people/(18)(1300)? Im still not understanding part b and c
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    Solving the Solar Power Puzzle in the US

    Okay so I am guessing you do 1300W/180w to reach the amount of sq meters needed for each person which is 7.22. I am not sure what to do for part A still, but for part b would you just do .10(3500000) then divide by 7.22? Could you please explain it a little more
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    Solving the Solar Power Puzzle in the US

    Hey guys, so I missed like the last week of classes due to me being sick all the time but I got a homework problem that I am pretty sure I would have learned if I were in class last week but here it is: The area of the continental United States is approximately 3.5 x 10^6 mi^2, and its...