Recent content by Onodeyja

Homework Statement A right circular cone has vertex down and is 10 feet tall with base radius 5 feet. The cone is filled with a fluid having varying density. The density varies linearly with distance to the top. Here "varies linearly" means the quantities are related by an equation of at most...

Yes, I should have written the function as s instead of f. Θ = 34˚ = 17∏/90 ∆Θ = 2˚ = ∏/90 ∆s = s'(Θ)∆Θ = s'(17∏/90)(∏/90) ∆s = [1250/32 * cos(17∏/90)] * (∏/90) ∆s = 1.13 18.1 ft + 1.13 ft = 19.23 ft

Homework Statement A player located 18.1 ft from a basket launches a successful jump shot from a height of 10 ft (level with the rim of the basket), at an angle Θ = 34 degrees and initial velocity of v = 25 ft/s.A. Show that the distance s of the shot changes by approximately 0.255∆Θ ft if the...

And so it does indeed :P 30(sin(At)/t) + Bt = -10[log(t)/log(5^(1/3))] + 76 30(sin(3∏/30*5)/5) + B(5) = -10[log(5)/log(5^(1/3))] + 76 30(1/5) + 5B = 46 6 + 5B = 46 B = 8 Thank you so much for your help. =D

When t = 5 30(sin(At)/t) + Bt = -10[log(t)/log(5^(1/3))] + 76 30(sin(0.314*5)/5) + B(5) = -10[log(5)/log(5^(1/3))] + 76 0.164 + 5B = 46 5B = 45.84 B = 9.168

Now, I'm assuming that the equation is now: When t = 0 30(sin(At)/t) + Bt = 3∏ 30 lim t->0 (sin(At)/t) + B(0) = 3∏ 30A + 0 = 3∏ A = 3∏/30

I think I have it: lim t-> 0 sin(At)/t 1. Multiply by A to get: lim t->0 Asin(At)/At 2. Put the A out front: A lim t-> 0 sin(At)/At 3. lim t-> 0 sin(At)/At = 1 and then A * 1 = A So the lim t->0 sin(At)/t = A?

I know that if it was just sin(t)/t that the limit would be 1 (for this equation A would have to be 1 to make that work).

Homework Statement Find A and B so that f(t) is continuous everywhere. Homework Equations Suppose that: [PLAIN]http://img690.imageshack.us/img690/8531/eqwkshp3.png The Attempt at a Solution Well, I wouldn't be posting if I wasn't lost, but I will tell you what I've tried. I know that I...