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@Mark44 Yes, thank you. I was writing with my phone so I accidently made that mistake. Thanks for the help.

So we have: (2/5)^n+4 = (2/5)^(-2) From where n+4=-2 n=-6 From where (2/5)^(-6+4) = (2/5)^(-2) (2/5)^(-2) = (2/5)^(-2)

Then solve the task if you may? You're showing me what's wrong but not how to do it right.

Then we win (2^(n+4) * 2^2) / (5^(n+4)) = 25 = (2/5)^(n+4) * 4 = 25 = (2/5)^(n+4) = 25/4 = (2/5)^(n+4) = (5/2)^2 Now we can do: n+4 = 2 n = 2-4 n = -2 From where: (2^(-2)) / (5^(-2)) = (5^2)/(2^2) = 1/(2^2) * 5^2 = (5^2)/(2^2) = (5^2) / (2^2) = 25/4 = 25/4 = 25/4 Seems right to me.

2^(n+6)/5^(4+n) - 2 = 23

Okay, I'm new here, and I'm not familiar with the computer math writing. So can you help me?

No. the n+6 is together upon the 2, as well as 4+n

Homework Statement 2^n+6/5^4+n - 2 = 23 The equation is correct. You need to work the left side to come down to the 23 = 23 conclusion. What makes this task difficult for me is the fact that on the down side of the fraction, the number is 54+n which makes it impossible to work with the...