Hi, I need to find ∫ln(x+1)/(x^2+1)dx
I think it might involve recursive integration by parts, so first I set:
u=ln(x+1) dv = 1/(x^2+1)dx
du=1/(x+1)dx v=ArcTan(x)
∫ln(x+1)/(x^2+1)dx = ArcTan(x)Ln(x+1) - ∫ArcTan(x)/(x+1)dx
Then I integrated by parts again, so...