Recent content by ori

please help given insulator ball with radius R that charged with uniformed density p<0. the ball is charged with -3Q 3 colon charges with Q>0 each one, are found inside the ball (look at the draw) the charges found at triangle that it's sides are equal (each side length = d) and d<=2R...

we get too hard integral at that case: S r^2/(r^2+h^2)^(3/2) dr or something like that

where is my mistake: we take ball with radius sqrt(R^2+h^2) and look on the rounded bases: the area of this ball inside the cylinder. flow through bases / flow through all ball = bases area / all ball area gaus: all ball flow is Q/epsilon0 all ball area is 4pi(R^2+h^2) base area...

http://t2.technion.ac.il/~snoop/Q.gif Q is at one point R is the radius of this cylinder, it's height is 2h the cylinder is without the bases. how can i calculate the electric flow through it? the final answer is Q/[epsilon0*sqrt(1+R^2/h^2)]

u r wrong i got the right answer(exactly :) ) thank u anyway ( 100V-50V = 150U ===> u=v/3 E = -G*150*Me/7400*1000+0.5*150*(v/3)^2 v is 7370)

look u need get the exact answer with the given data i thought about: both bodies at the same speed , coz they collided, what means they at the same high. so i tried momentum conservation : 1)m1*V-m2*V=m3*V3 and while r1 is 6400+1000 km i used the equations 2) V^2=GM/r1 3) V3^2=GM/r3...

but there's also kinetic energy plus the distance from Earth is changed i think

i don't understand why it is just to assign the value to the potential equation?? i also don't get the right answer with assign the values (with 6400 or 6700 for Re) it with the equation. ( i get something pretty close though -7831.17 * 10^6)

when body that it's is 100kg is at 1000km above earth, he collides with another body that it's mass is 50kg that moves infornt of him. the bodies stick together and becoming to one big body that it's mass is 150kg what's the enegry of the new body? given data: Re=6400km R2=1000km...

training for test that's what i did, could anyone tell what's my prob here: for first particle T=mc^2(r-1) since we're working with Mev , c=1 T=m(r-1) r=T/M+1 therefore (1) V^2=T/(T+M) (V is speed of particle one according to "the lab") therefore the speed of particle2 is -V...

2 particles with mass M and Kinetic Engergy T moving toward each other. what is the kinetic energy T' as it measured by the other particle given data: T=... m=... thanks

look guys if i was writing stoke's theorem it was borring if I am writing stocks theorem, it's attracts ppl to read - maybe there's a new mathmatical theorem about stocks etc.. plus it sound like stoke's.. (kiddin :rolleyes: , it just a spelling mistake)

10x my native lang is hebrew

c is a curve of the cutting of the to surfaces: x^2+y^2=1 z=xy at the point (1,0,0) the tangent to C is toward j^ so what is S(xz^2-y)dx+(3x-yz^2)dy+(zx^2-zy^2)dz C ? hmm.. i calculated this vectorian field rotor: it's (0,0,4) i know i should use stocks and make it SS(0,0,4)*n^ ds...

i found my mistake at the ingeral just how i choose the shape please?