That what I did at first, and I got wrong answer. But I found calculation mistake, now it work and give correct answer. The third part need to be:
$$\int_{1.5}^{2}\int_{x-0.5}^{2}f(x,y)dydx$$
Ok, I understand how to set that specific boundaries. But why in the first "1" quadrant area when I...
Sorry, you right! this |x-y| I confused for a moment.
I'm trying to calculate this one: $P(|X-Y|<0.5)$. Where do I enter that "plot" command? do I need MATLAB or something?
However, I need to find answer. Finding the first quadrant is just part of the process that I think is relevant for...
Hi,
I have homework question that I'm trying to solve. But I can't understand the basis.
Here is a picture of the question and what I have done:
My question is, How do I set the boundaries for the integral? 1. If I want the whole squart. 2. To sum up areas.
Assume I want to sum the areas, I...
There is lucky machine with 3 results (letters):
A,B,C
P(A)=0.2 (Probabilty to get A)
P(B)=0.3 "" "" ""
P(C)=0.5
Each round you get just one letter.
You played 5 times.
What the probability that you got three times "A" and two times "B".
i thinked to do that...
Ok Actually R={<1,1>,<2,2>,<3,3>} is identity relation on A for sure.
But what prevent from R= {<1,1>,<2,2>} to bo identity on A?
It not writed $$\forall$$ x $$\in$$ A.
Let A= {1,2,3}.
Let R= {<1,1>,<2,2>}.
I(A) (Identity Realtion) on A >(def)> {<x,x>|x $$\in$$ A}
So that mean : $$\forall$$ <x,x> x $$\in$$ A
(That how I understood it)
My question:
Is R is identity relation on A ?
Thank you !