Recent content by ozzy

yes and no... yes in terms of expanding the problem to something universal... no in terms that I still can't understand how it is possible that the second integral is not zero, but the fourth suppose to be a zero... I understand that there is some problem with the assumptions...I just don't...

Yes, I also have this intuition, and regarding what you say, the last integral, with zero outcome is the right one, since the plane in missile system doesn't travel over Y axis. But since the second integral is the right one, and not fourth, it seems that the plane travels over distance...

The answer for the original question is found here: But please help me with the current, new question, which is MY question, and not from the book...

Well, I am sorry to bother you again, but it seems that after solving my last problem nobody enters that topic anymore :rolleyes: I hope I won't get on moderators nerves here... Well, anyway. As one may remember, I asked about this question: an aircraft flights at height H with a constant...

Well, thinking about the problem a little bit further, I have another problem: the relative velocity between the missile and the plane in Cartesian axis is: Vx(t) = V*cos{f(t)} - U Vy(t) = V*sin{f(t)} - 0 and initial position,that should preserve is R = (0 , H) therefore: \int_{0}^{T}...

Oh, I think I see it - the initial distance between the plane and the missile is H, therefore the relative distance that a missile has to cover is D=H... YOU ARE THE KING!

THANX! It all seems very clear and right, except the last line - how can you see that d=H?

this is the right answer:) but I could find it in the answers of the book... can you please give us some guiding lines to the solution?

If you check my second post, you will see that i mentioned that HallsofIvy made a mistake! it should be: \sqrt{ (\frac{dx}{dt})^2 + (\frac{dy}{dt})^2 } = V and so \sqrt{ 1+ (\frac{dy}{dx})^2 } = \frac{V}{(\frac{dx}{dt}) } or \frac{dy}{dx} = \sqrt{(\frac{V}{\frac{dx}{dt}})^2 - 1}

I solved these equations numerically in Matlab : Vx = dX/dt = v*(u*t - X) / sqrt((u*t - X)^2 + (H - Y)^2) Vy = dY/dt = v*(H - Y) / sqrt((u*t - X)^2 + (H - Y)^2) => dX/dY = (u*t - X) / (H - Y) v^2 = (dX/dt )^2 + (dY/dt)^2 => H=10; u=5; v=6; X(1) = 0; Y(1) = 0; dt =...

For two weeks I can't solve this question with my friends. Please help us! an aircraft flights at height H with a constant velocity U. When it passes right above the missile, the missile is fired with a constant velocity V (V>U), but the vector of the velocity of the missile points directly...