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padmaraju bapala
Recent content by padmaraju bapala
Equivalent Power In series and parallel combination
since in a series circuit having e resistances r1, r2, r3, R = r1+r2+r3 then I²R = i1²*r1+i2²r2+i3²r3, (since I = i1 = i2 = i3) then P = p1+p2+p3 but how actually it be 1/P = 1/p1+1/p2+1/p3
padmaraju bapala
Post #18
May 13, 2017
Forum:
Electrical Engineering
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padmaraju bapala
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