Recent content by Paladashe

No as you said before, we can't assume that both pin have the same vertical forces (25-25). Or, if Rby is equal to 25 and that EFy=0 <=> -50+25+Ray=0 :) so Ray is equal to 0 which is impossible

Can you give me your result ? Is it 37,5?

-50?

yes but it's not working for me :p could you please try to explain why my equation is wrong ? Please ! I'm getting a headache by trying and trying :p

Yes, but by doing my equation , I found that Rb=50N so R(vertical) is equal to 0??

Yes but don't know how to do this because its not perpendicular to the line of action:)

Where a is the pin fixed and b the roller pin

The moment equation, right? ... EMa=-50•3•12,1244 + 50(square root of 3)•7 + 4•12,1244•Rb ?

Thanks Tiny-tim for your response. In fact, I now for vertical external forces and horizontal ones so I divided the 100N vector in two vectors (one with a value of 50N orientated downwards and one with a value of 50•(square root of 3). I found that each pin has a vertical vector orientated...

Hi, I'm new on this website and it seems great :p So, I'm struggling with something really simple... trusses analysis. I'm struggling with moments etc , I've just drawn an example linked in this post , could you try to find the reaction forces (roller pin etc) with some explanation ? Thanks