Recent content by panadaeyes

Yah, I haven't learned L'Hopital's Rule yet But thanks guys!

Okay, so I split them up, but would the equation: lim h->0 of sin h/ h = 1 be the same as the lim h->0 of h/sin h?? how does that work? and therefore be: 1 * lim h->0 (1+ cos h) = 1 * 2 = 2?

Homework Statement Find the Limit: lim h->0 of ( h sin h)/ ( 1-cos h) Homework Equations lim h->0 of (sin theta)/ theta = 1 lim h->0 of (cos(h)-1)/h=0 The Attempt at a Solution lim h->0 (h/1-cos h)*(sin h) * (1+cos h/ 1 +cos h) = lim h->0 (h(1+cos h) * sin h)/(1-cos^2 h) =...