Its simple. Multiply your numerator and denominator by e^x. This will get you (2e^2x)/(e^2x + 1)dx. Now suppose your whole denominator as another variable,say, t. Calculate dt which will be equal to 2e^2xdx.
So now your integral is in the form of (1/t)dt. Integration of this will give you...
Yeah thanks for this example.
I did some digging too and found out that all power signals are periodic in nature, and it is impossible to write Fourier transform of periodic signals. They can only be represented by Fourier series.
And also according to you..fourier transforms are supposed to...
Thank you..but i still have one doubt...in your explanation about Fourier transform.
As much as i know Fourier transform do exist for f_1(t) = Asin wt
It would be F_1(f) = iA/2 [(f+fm) - (f- fm)]
taking w = 2 pi fm
Now f_1(t) is a power signal then why its Fourier transform is available?
I have read that for
power signals : power = finite and energy = infinite
Energy signals : power = 0 and energy = finite
Can anyone give practical example for this...?
Also we can represent power signal through Fourier series only but not through Fourier trransform..unlike energy signals...