Recent content by Paul_Bunyan

Hi guys, Sorry for resurrecting a super old post, but ironically enough I have some more questions about this exact same problem... So, if I give the beam a length value "L," I can find the torque caused by the crate force with 1906*L*Cos(30), is that right? But then I'm stuck on how...

Here's a picture: OK, so contact is lost when mv^2/r = cos(theta)mg (cos(theta)mg being the radial component of mg). That makes sense. So then v^2/r = cos(theta)g, and v^2 = cos(theta)gr. I read through that other problem you linked to, so I assume the answer would be the same here...

Homework Statement A person starts from rest at the top of a large frictionless spherical surface, and slides into the water below. At what angle (theta) does the person leave the surface? Then the book gives a "hint": (Hint: The person will lose contact with the surface when the Fn...

Homework Statement OK, here's the scenario: We have a helicopter lifting someone out of the water via a rope. The person has a mass of 79kg and he is being accelerated upwards at 0.7m/s^2. I also need to calculate work being done by the tension in the cable and by the person's weight...

Thanks for your advice...haha. :rolleyes:

Well, I'm not sure if this is the right place for this question, but it seemed like a good place for it, heh... My question is, in Maple 10, how do you change the default units? More specifically, the program comes with the default angular unit as Radians, and I want to change it to Degrees...

You're right, I went through it kind of fast and had a wayward "-" sign. After fixing that I got: T1 = 917.456 T2 = 844.18 Which makes a lot more sense, is that close to what you got?

Yeah, I think I get it now, thanks a bunch!

So, in the vertical part: T1 Cos 65 + T2 Cos 80 = 535 Doesn't the 535 take into account the weight of the climber? Since the two verticle upward forces of each rope must add together to equal the single downward force due to the mass of the climber?

Ahhh, of course! I can't believe I overlooked that...I was thinking too much, thanks. So, after doing all the algebra and trig, I came up with this... From the equations for the components: T1=Left, T2=Right T1 Sin 65 + T2 Sin 80 = 0 T1 Cos 65 + T2 Cos 80 = 535 Left string's...

Homework Statement A climber is suspended between two cliffs and is closer to the left cliff. The left part of the rope makes an angle of 65 to the cliff and the right part an angle of 80 to the cliff. The climber weighs 535N. Homework Equations Trigonometry... The Attempt at...