Recent content by PaulingL

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    Volume of a Solid: Washers/Disks/Shells

    Hmm. I have tried many combinations (I am on attempt 37), to no avail. I have tried (x^(2/5)) as well.
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    Volume of a Solid: Washers/Disks/Shells

    Here is a picture of the problem: http://i.imgur.com/0usxa.png
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    Volume of a Solid: Washers/Disks/Shells

    The integral is not pi(x^(1/5)^2) or pi(x^(1/5))
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    Volume of a Solid: Washers/Disks/Shells

    Could you tell me how you did it? I have to enter the integral for the answer.
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    Volume of a Solid: Washers/Disks/Shells

    It is saying correct for dx and incorrect for dy. I am sure you could do it both ways, but they clearly want me to use dx.
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    Volume of a Solid: Washers/Disks/Shells

    Thanks so much for helping me. I have spent far too much time working on this problem!
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    Volume of a Solid: Washers/Disks/Shells

    Yes, I did mean pi, sorry about that. Thanks for the reply! On "WebWork" (the software my school uses) we are required (for this homework) to report it all as one integral. I have drawn out the two "interpretations" I had of this problem and took a photo of it. I hope it is clear enough to...
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    Volume of a Solid: Washers/Disks/Shells

    Homework Statement The volume of a solid obtained by rotating the region enclosed by x=0, y=1, x=y^5 about the line y=1 can be computed using the method of disks or washers via an integral.Homework Equations V= ∏\int(R^2-r^2)dx The Attempt at a Solution I have attempted this problem many...
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