Alright thank you. this makes a lot of sense now. The way I was doing it, the unit analysis didn't work because you ended up with hyphen-lightyears/s but the answer(number) was the same but you really just wanted hyphens per second.
So if we measure the rate of change by d/s then we are...
Why is it (hyphen/lightyear)/second? If you are adding an additional hyphen for each light year are you not multiplying 1 hyphen by the amount of light years between objects? 1/3 =/= 3 additional hyphens. where 1*3 does.
So if I understand correctly; If you measure the rate of change as 1 hyphen/second, then you must be at the center to observe equal expansion but if you measure the rate of change as (1 hyphen x light year)/second then your position could be anywhere and you would still observe equal expansion?
Thank you for helping me understand. I think I have a good idea on the concept now. I do have one question though. If each line has the distance between arrows increased by one hyphen per line, could you not state the rate of expansion is one hyphen per arrow per line?
Say each line represents...
This is not necessarily true. If everything is expanding at the same rate, then no matter which area you are looking from, everything would appear to be expanding away from you at the same rate.
The only catch would be that you could not be at the edge of the universe because then it would...
Homework Statement
Find the Average Grain Diameter
Homework Equations
d= C/NLM
The Attempt at a Solution
My instructor hasn't defined what C or M are. I could easily solve this equation if I just knew which numbers I am supposed to substitute in for C and M. NL is the average...
Hi,
This is my first post as I am new to these forums but I was searching for a database which could give me practice questions along with solutions for introductory physics. I am currently in a first year physics course at the University of Lethbridge. The course deals with mechanics, linear...