Recent content by penelopa

And that is just a problem: a radar measurement gives only a... number: ##v'=\frac{v_o-v_r}{1-v_ov_r}## instead of the correct - desired: ##v = v_o-v_r##.

I ignored Your Doppler formula earlier, without any comment, but it's evidently wrong. The correct formula is in my post #2. It's of two-variable function. So, it's impossible to recovery these two variables by one measurement only, and even a difference of the both: vs-vo, because the function...

I named the v as a real speed, because I know the distance to the Moon, and I have an clock, then I can determine a flying time: d = vt;

But You can see, I use the both: relativistic and classical together! I'm discovered successfully the classical radar Doppler shift, using the relativistic speed composition idea only: ##v'=\frac{v_o-v_r}{1-v_ov_r}## One additional question: what is a rocket speed which is flying with a speed...

I understand what You are talking about, but I'm interested in the real speed of my rocket, which is determined perfectly to be: ##v=v_o-v_r##, because the rocket's trajectory has been projected precisely to be just that, not any other. But a radar gives me this...

I can provide a better example: we shoot a rocket to the Moon, for example. The rocket accelerates at the beginning, and we know what is the acceleration precisely; and further it moves freely in a space with a speed which we know already, because we projected precisely the whole journey. Now...

My setup is a typical measurement of a speed of moving body, using a radar. Radar-->vr <===singnal===> O - My car --->vo The Radar can't measure the speed's difference, which is equal to: ##v = v_o-v_r##, nor my car speed: ##v_o ##. It can measure something like the relativistic speed only...

What a range rate? The shift evidently depends on the two variables: vr and vo. And there is no possibility to measure the real speed difference: vr-vo, in which we are interested!

So, I can conclude finally: the speed's measurement, by the Doppler shift observation, is impossible in principle, because the Doppler shift is a function of two variables in fact: a speed of an measured object, and a speed of a radar itself, not a single one number, which can be rediscovered by...

I try to rediscovery the original classical version, in this way: SR assumes the relative speed is equal to: ##v=\frac{v_s-v_r}{1-v_s\cdot v_r}## therefore if I simply insert this into the relativistic equation, then I should get just the classical version, I think...

I think the relativity provides the Doppler shift (in a radar - double version) in a form: ##\frac{1-v}{1+v}## which is quite simple, as a square of a single Doppler: ##f' = f\sqrt{\frac{1-v}{1+v}}## But I never seen what is a classical version of this - what is a formula for a radar shift in...